Exiting an order with order_id. (Reverse Order with order_id)
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Hi,
I place an order using the below code. It creates a new order, say order_id: 1. Now I want to exit this order_id(1). How do I do this? I can get the executed order_ids from Order Book or Trade Book. But how do I place a reverse order for a particular order_id. Every time I use the below code it creates a new order.
I want to know how to close an exiting order using order_id or any other way to close and existing order.Please help. Thank you.
orderparams = {
"variety": "NORMAL",
"tradingsymbol": script,
"symboltoken": token,
"transactiontype": BUY/SELL,
"exchange": exchange,
"ordertype": "LIMIT",
"producttype": "INTRADAY",
"duration": "DAY",
"price": ltp,
"squareoff": "0",
"stoploss": "0",
"quantity": quantity
}
orderId = obj.placeOrder(orderparams) -
@Meghavarsha said in Exiting an order with order_id. (Reverse Order with order_id):
I want to know how to close an exiting order using order_id or any other way to close and existing order.
There is no mechanism to close a position using order id. The way to do it is to place an opposite BUY or SELL order depending on whether the position is a long or a short. You can fetch open positions from here - https://smartapi.angelbroking.com/docs/Portfolio#position
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@admin Related question, how do we do this for a ROBO order where the main order is completed and the two sub-orders are not. Basically this is like squaringoff the order. Unlike the given example, though we can place a new order but we have to cancel the two sub orders, cancelOrder fails.